A man drove from Aardvark to Beeville. On the first day he travelled 1/3 of the distance. On day two he travelled 1/2 of the remaining distance. On day three he travelled 2/3 of the remaining distance. On day four, after covering 3/4 of the remaining distance, he was still 5 miles away from Beeville. How many miles had he covered so far?
October 2nd, 2011 | Category: 
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Covered during day 1 = 1/3 = > Remaining = 1 – 1/3 = 2/3
Covered during day 2 = 1/2 * 2/3 = 1/3 = > Remaining = 2/3 – 1/3 = 1/3
Covered during day 3 = 2/3 * 1/3 = 2/9 = > Remaining = 1/3 – 2/9 = 1/9
Covered during day 4 = 3/4 * 1/9 = 3/36 = > Remaining = 1/9 – 3/36 = 1/36
Knowing that 1/36 = 5 miles
=> Total distance = 180 miles
=> Covered distance = 175 miles
Correct, Rool!
He had covered 175 miles so far — the total trip was 180 miles. Working backwards:
Day 4: travelled 3/4 leaving 5 miles, which means that 5 miles is 1/4, so 20 miles were left at the start of Day 4.
Day 3: travelled 2/3 leaving 20 miles, which means that 20 miles is 1/3, so 60 miles were left at the start of Day 3.
Day 2: travelled 1/2 leaving 60 miles, which means that 60 miles is 1/2, so 120 miles were left at the start of Day 2.
Day 1: travelled 1/3 leaving 120 miles, which means that 120 miles is 2/3, so 180 miles were left at the start of Day 1.
Of the 180 miles overall, 175 were covered in the 4 days.
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