Like a normal car, my new i10 has five wheels (two in front, two in rear plus a spare).
The rear wheels of the car will wear out after 21,000 miles and the front wheels will wear out after 29,000 miles.
What is the maximum distance I can drive assuming replacing the tires is not an option.
July 30th, 2013 | Category: 
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What did you mean by replacing the tires is not an option??? If there is no replacing then 21000 max.
You cannot replace them with new tires. You can rotate them, however.
Wouldn’t the front tires wear out faster than the rear tires in an i10? It is front wheel drive so the front tires deal with the power, the steering, most of the stress from breaking, and the weight of the engine…
No, don’t confuse this i10 with a Hyundai. With this car, the tires wear out as indicated.
Keep trying.
26,250 miles.
New guess with better math.
30,450 miles. Each tire spending 6,090 miles as the 5th wheel (spare), 12,180 miles on the front (58% of the tire’s front wheel life) and 12,180 miles on the back (42% of the tire’s back wheel life)
Probably not though
29,000 is my guess but it’s probably wrong
When I said probably not though that was about my guess
Great job, Deep Fat Fryer.
Maximum distance: 30,450 kilometers.
For each 5 kilometers driven using this rotation, each tire will lose (2/29000)+(2/21000) of its tread.So, suppose we drive 5*N kilometers like this. Then, each tire will lose 2*N*((1/29000)+(1/21000)) of its tread. We wish to determine N so that the latter expression gets to be 1, representing all of each tire’s tread. That happens when N=6090, which is when 5*N (the total kilometers driven) is 30,450.”; $SOLUTION=”13 x 3 + 1 = 40.
You are today’s winner.