# Rated Rrrrrrrrr

Ten pirates find a buried treasure of 100 pieces of gold.

The pirates have a strict ranking in their group: Pirate 1 is the lead pirate, Pirate 2 is second-in-command, Pirate 3 is the third most powerful pirate, and so on.

Based on this ranking, the pirates decide on a system to determine how to split up the 100 pieces of gold. The lead pirate (Pirate 1) will propose a way to divy it up. Then all the pirates (including the lead pirate) will vote on that proposal. If 50% or more of the pirates agree on the system, then that is how the gold will be divied up. However, if less than 50% of the pirates vote for the proposal, then the lead pirate will be be killed. The next-most powerful pirate will then become the lead pirate, and they’ll restart the process (Pirate 2 will suggest a way to divy up the gold and it will be voted on by the rest of the pirates). This will keep going on until finally a proposal is agreed upon.

All of the pirates are very smart and very greedy. Each pirate will vote against a proposal if they know that they would end up with more gold if that proposal were to fail. A pirate also will never vote for a proposal that gives him zero pieces of gold.

You are Pirate 1. You must come up with a proposal that will give you as much gold as possible, without getting yourself killed. Keep in mind that the rest of the pirates all know that if your proposal fails, then Pirate 2 will succeed at coming up with a plan that benefits him the most while not getting him killed.

### 7 guesses to Rated Rrrrrrrrr

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• Nanao Ise

Perhaps it might be passable to divide the gold as such?

pirate 1: 96 pieces of gold

pirate 2: 0 pieces of gold

pirate 3: 0 pieces of gold

pirate 4: 0 pieces of gold

pirate 5: 0 pieces of gold

pirate 6: 0 pieces of gold

pirate 7: 1 piece of gold

pirate 8: 1 piece of gold

pirate 9: 1 piece of gold

Basing this on the assumption that the last four pirates would be grateful to get anything and that they probably wouldn’t get anything if the lead pirate is killed and pirate two becomes its successor.

• Nanao Ise

Apologies – I forgot to include pirate 10, who receives 1 piece of gold as well.

• You are very close, but not correct.

Remember, the situation changes slightly when there is an even number of pirates vs. an odd number.

Try again.

• Ryver

pirate 1: 96 pieces of gold

pirates 3 – 6: 1 piece of gold each

As pirate 1, I will say: If pirate 2 becomes leader, he will have 96 while the current pirates 7, 8, 9, and 10 (who will become 6,7,8, and 9 respectively at the death of pirate 1) will get 1 gold each. Therefore, if pirates 3-6 do not vote for me, pirate 2 will give them 0 gold.

• Nanao Ise

Hmmmâ€¦

Perhaps, then, pirate one gets 96 pieces of gold. Then pirates 3, 5, 7, and 9 each get one gold piece each.

This way, if [I] am killed, then pirates 3, 5, 7, and 9 will receive nothing?