An insurance company issues life insurance policies in three separate categories: standard, preferred, and ultra-preferred.

Of the company’s policyholders, 50% are standard, 40% are preferred, and 10% are ultra-preferred.

Each standard policyholder has probability 0.010 of dying in the next year, each preferred policyholder has probability 0.005 of dying in the next year, and each ultra-preferred policyholder has probability 0.001 of dying in the next year.

A policyholder dies in the next year. What is the probability that the deceased policyholder was ultra-preferred?

(A) 0.0001

(B) 0.0010

(C) 0.0071

(D) 0.0141

(E) 0.2817

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Nope, keep trying.

0.0001?

Nope, that’s not it.

Please show how you arrived at the answer.

It’s (D) 0.0141.

10 x 0.001 = 0.01

40 x 0.005 = 0.2

50 x 0.01 = 0.5

Add these together: 0.01 + 0.2 + 0.5 = 0.71

Now divide the ultra-preferred by the total: 0.01/0.71 = 0.01408 or 0.0141

You are correct, Big Daddy.

50 x .010 = .0050

40 x .005 = .0020

10 x .001 = .0001

Total: 1 = .0071

1/71 – 0.0141 So the answer is D.

You are today’s winner.