An insurance company issues life insurance policies in three separate categories: standard, preferred, and ultra-preferred.
Of the company’s policyholders, 50% are standard, 40% are preferred, and 10% are ultra-preferred.
Each standard policyholder has probability 0.010 of dying in the next year, each preferred policyholder has probability 0.005 of dying in the next year, and each ultra-preferred policyholder has probability 0.001 of dying in the next year.
A policyholder dies in the next year. What is the probability that the deceased policyholder was ultra-preferred?
(A) 0.0001
(B) 0.0010
(C) 0.0071
(D) 0.0141
(E) 0.2817
May 17th, 2011 | Category: 
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iwould say 0.0010
Nope, keep trying.
0.0001?
Nope, that’s not it.
Please show how you arrived at the answer.
It’s (D) 0.0141.
10 x 0.001 = 0.01
40 x 0.005 = 0.2
50 x 0.01 = 0.5
Add these together: 0.01 + 0.2 + 0.5 = 0.71
Now divide the ultra-preferred by the total: 0.01/0.71 = 0.01408 or 0.0141
You are correct, Big Daddy.
50 x .010 = .0050
40 x .005 = .0020
10 x .001 = .0001
Total: 1 = .0071
1/71 – 0.0141 So the answer is D.
You are today’s winner.