Three Old Coins

A woman had three old coins – a silver dollar, a quarter, and a dime. Each coin was a little battered and had a piece missing.
She found that exactly the same fraction had broken away from each coin. What fraction of each was missing if the value of the remaining
bits of coins was now exactly one dollar in total? For this puzzle it can be assumed that half of a coin is worth half of its value.

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April 17th, 2013 | Category: Brain Riddle, Mathematical, Money |  Email This Riddle

2 guesses to Three Old Coins

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• Ryver

  April 18, 2013 at 10:11 AM

  Algebra Time! X = bit remaining
  1X + .25X + .1X = 1
  1.35X = 1
  X = approx. 74%
  1-X = approx. 26%

• Dude

  April 19, 2013 at 7:24 AM

  Correct Ryver.

  7÷27 of each coin was missing.

  The original value of the three coins was 100 + 25 + 10 = 135, and the new value was 100. So 35÷135 of the original value has been removed and 35÷135 = 7÷27 (Which is approximately 26%)

  You’re today’s winner.