A woman had three old coins – a silver dollar, a quarter, and a dime. Each coin was a little battered and had a piece missing.
She found that exactly the same fraction had broken away from each coin. What fraction of each was missing if the value of the remaining
bits of coins was now exactly one dollar in total? For this puzzle it can be assumed that half of a coin is worth half of its value.
Warning: Use of undefined constant bfa_comments - assumed 'bfa_comments' (this will throw an Error in a future version of PHP) in /home/customer/www/riddledude.com/public_html/wp-content/themes/atahualpa/comments.php on line 132
Algebra Time! X = bit remaining
1X + .25X + .1X = 1
1.35X = 1
X = approx. 74%
1-X = approx. 26%
Correct Ryver.
7÷27 of each coin was missing.
The original value of the three coins was 100 + 25 + 10 = 135, and the new value was 100. So 35÷135 of the original value has been removed and 35÷135 = 7÷27 (Which is approximately 26%)
You’re today’s winner.