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May 2024
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Ancient Math Riddle

Ancient Math Riddle
Take 9 from 6, 10 from 9, 50 from 40 and leave 6.

How Come ?

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6 guesses to Ancient Math Riddle


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  • Crabman

    Using some funny binary maybe?

    First, binary/base 10 equivalents
    110 = 6
    1001 = 9
    1010 = 10
    101000 = 40
    110010 = 50

    If there are the same # of 1’s in the two numbers the answer is 1, if there are a different amount of ones, the answer is zero. I realize this is a stretch, but the last number riddle counted closed areas, multiplied by digets without closed areas, so I’m just taking a shot. Only thing I could come up with.

    110 – 1001 = 1 (same # of 1s)
    1001 – 1010 = 1 (same # of 1s)
    101000 – 110010 = 0 (different # of 1s)

    Combine these and you get 110, convert from binary to base10 and you get the 6.

  • Sorry Crabman, that was not what I was looking for.
    That ROMAN way of looking at numbers should keep you trying.

  • Frank

    VI – IX = V-X
    IX – X = I
    XL – L = X

    V-X + I – X = VI = 6

  • Frank

    Should be (changed – to +)
    VI – IX = V-X
    IX – X = I
    XL – L = X

    V-X + I + X = VI = 6

  • Achu

    Use roman numerals:
    Remove nine(IX) from SIX = SIX – IX = S
    Take 10(X) from 9(IX) = IX – X = I
    Take 50(L) from 40(XL) = XL – L = X
    So the answer would be SIX. (6)

  • Achu, you are today’s winner!
    SIX – 9 (IX) = S. 9 (IX) – 10 (X) = I. 40 (XL) – 50 (L) = X => SIX