Take 9 from 6, 10 from 9, 50 from 40 and leave 6.

How Come ?

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Warning: Use of undefined constant bfa_comments - assumed 'bfa_comments' (this will throw an Error in a future version of PHP) in/home/customer/www/riddledude.com/public_html/wp-content/themes/atahualpa/comments.phpon line132Using some funny binary maybe?

First, binary/base 10 equivalents

110 = 6

1001 = 9

1010 = 10

101000 = 40

110010 = 50

If there are the same # of 1’s in the two numbers the answer is 1, if there are a different amount of ones, the answer is zero. I realize this is a stretch, but the last number riddle counted closed areas, multiplied by digets without closed areas, so I’m just taking a shot. Only thing I could come up with.

110 – 1001 = 1 (same # of 1s)

1001 – 1010 = 1 (same # of 1s)

101000 – 110010 = 0 (different # of 1s)

Combine these and you get 110, convert from binary to base10 and you get the 6.

Sorry Crabman, that was not what I was looking for.

That ROMAN way of looking at numbers should keep you trying.

VI – IX = V-X

IX – X = I

XL – L = X

V-X + I – X = VI = 6

Should be (changed – to +)

VI – IX = V-X

IX – X = I

XL – L = X

V-X + I + X = VI = 6

Use roman numerals:

Remove nine(IX) from SIX = SIX – IX = S

Take 10(X) from 9(IX) = IX – X = I

Take 50(L) from 40(XL) = XL – L = X

So the answer would be SIX. (6)

Achu, you are today’s winner!

SIX – 9 (IX) = S. 9 (IX) – 10 (X) = I. 40 (XL) – 50 (L) = X => SIX